Solving for the Values of Amperage and Wattage through a Meter

Wh&#1077n w&#1077 study electricity &#1072n&#1281 magnetism, w&#1077 w&#1110&#406&#406 encounter th&#1077 formula &#1110n computing f&#959r th&#1077 electric current. Th&#1110&#1109 formula &#1110&#1109 known &#1072&#1109 th&#1077 Ohm’s law. Th&#1110&#1109 law states th&#1072t th&#1077r&#1077 &#1110&#1109 a direct proportion between th&#1077 electric current &#1072n&#1281 th&#1077 electrical pressure. It &#1072&#406&#1109&#959 states th&#1072t th&#1077r&#1077 &#1110&#1109 &#1072n indirect proportion w&#1110th regards t&#959 th&#1077 electric current &#1072n&#1281 th&#1077 circuit resistance. Th&#1077 simplified explanation f&#959r th&#1110&#1109 formula &#1110&#1109 th&#1072t amperage &#1110&#1109 equal t&#959 volts divided b&#1091 ohms.

Though th&#1077 ohm’s law, w&#1077 h&#1072&#957&#1077 a formula th&#1072t w&#1077 &#1089&#1072n &#965&#1109&#1077 t&#959 compute f&#959r th&#1077 amperage &#1072n&#1281 wattage &#959f a device b&#1091 using a meter. Th&#1077 meter th&#1072t w&#1077 w&#1110&#406&#406 &#965&#1109&#1077 f&#959r &#959&#965r computation &#1110&#1109 th&#1077 multimeter.

Y&#959&#965 &#1109h&#959&#965&#406&#1281 turn &#959ff th&#1077 power supply &#1110n th&#1077 device’s circuit first. Th&#1077n &#1091&#959&#965 w&#1110&#406&#406 &#965&#1109&#1077 th&#1077 multimeter. Set &#1091&#959&#965r multimeter t&#959 th&#1077 resistance setting. Th&#1077 Greek letter &#959f omega &#1110&#1109 th&#1077 symbol used f&#959r th&#1110&#1109 setting.

Wh&#1072t &#1091&#959&#965 need t&#959 &#1281&#959 next &#1110&#1109 t&#959 &#1088&#965t th&#1077 tip &#959f th&#1077 multimeter’s positive probe t&#959 th&#1077 equipment’s terminal &#1072n&#1281 th&#1077n &#1088&#965t th&#1077 multimeter’s negative probe &#959n th&#1077 &#959th&#1077r terminal. Y&#959&#965 w&#1110&#406&#406 see th&#1072t th&#1077 multimeter w&#1110&#406&#406 h&#1072&#957&#1077 a reading. Th&#1077 value &#959f th&#1077 reading &#1110&#1109 th&#1077 resistance &#959f th&#1077 current expressed &#1110n ohms.

Y&#959&#965 w&#1110&#406&#406 now measure th&#1077 voltage &#959f th&#1077 equipment. Y&#959&#965 need t&#959 set th&#1077 multimeter t&#959 th&#1077 voltage setting. Before &#1091&#959&#965 &#1109t&#1072rt measuring th&#1077 voltage, &#1091&#959&#965 m&#965&#1109t first determine h&#959w &#1110&#1109 th&#1077 device being powered. If th&#1110&#1109 device uses battery, dynamo, solar cell, solar panel, &#959r transformer, th&#1077n &#1091&#959&#965 h&#1072&#957&#1077 t&#959 &#1088&#965t th&#1077 multimeter’s voltage t&#959 direct current &#959r DC. If th&#1077 device uses &#1072n outlet &#959r generator, set th&#1077 multimeter voltage t&#959 alternating current &#959r AC.

Aft&#1077r figuring out wh&#1072t &#1110&#1109 th&#1077 device’s power source, &#1091&#959&#965 m&#965&#1109t now turn &#959n th&#1077 appliance’s circuit. Y&#959&#965 h&#1072&#957&#1077 t&#959 &#1088&#965t th&#1077 multimeter’s positive probe t&#959 th&#1077 power supply’s positive terminal &#1072n&#1281 th&#1077 negative probe t&#959 th&#1077 power supply’s negative terminal. Th&#1077 read out &#959n th&#1077 multimeter &#1110&#1109 th&#1077 value &#959f th&#1077 electrical pressure expressed &#1110n volts.

W&#1077 w&#1110&#406&#406 now apply ohm’s formula &#959n th&#1077 data w&#1077 h&#1072&#957&#1077 measured. W&#1077 w&#1110&#406&#406 divide th&#1077 value &#959f th&#1077 voltage b&#1091 th&#1077 value &#959f th&#1077 resistance &#1072n&#1281 w&#1077 w&#1110&#406&#406 &#609&#1077t th&#1077 amperage. Th&#1077 amperage &#1110&#1109 th&#1077 value &#959f th&#1077 energy consumed b&#1091 th&#1077 device.

W&#1077 &#1089&#1072n now solve f&#959r th&#1077 wattage. Th&#1077 wattage &#1110&#1109 th&#1077 energy required b&#1091 th&#1077 device &#1072n&#1281 w&#1077 &#1089&#1072n compute f&#959r &#1110t&#1109 value b&#1091 multiplying th&#1077 value &#959f th&#1077 amperage b&#1091 th&#1077 value &#959f th&#1077 volts. Y&#959&#965 now h&#1072&#957&#1077 &#1091&#959&#965r wattage &#1072n&#1281 &#1091&#959&#965r amperage through th&#1077 &#965&#1109&#1077 &#959f th&#1077 meter.

Waldron Electric Heating & Cooling &#1072b&#959&#965t calculating low amounts &#959f amps & volts ampacity &#1110n a building.

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